What thrust would be required to hold position against a 60-knot wind based on a known thrust of 12,000 pounds at 10 knots?

To determine the correct thrust required to hold position against a 60-knot wind based on the known thrust of 12,000 pounds at 10 knots, it is essential to understand the relationship between wind speed, vessel thrust, and the forces acting on the vessel.

The relationship can be derived using the concept of thrust proportionality. Thrust required increases with the square of the speed of the wind. Since thrust is proportional to the square of the speed, we can use the following proportionality:

[

\text{Thrust required} \propto \text{Wind speed}^2

]

Given that the thrust at 10 knots is 12,000 pounds, we can set up a ratio to find the required thrust for 60 knots:

1. Calculate the ratio of the wind speeds:

[

\text{Ratio} = \left( \frac{60 \text{ knots}}{10 \text{ knots}} \right)^2 = 6^2 = 36

]

2. Multiply the known thrust (12,000 pounds) by this ratio:

[

\text{Thrust needed at 60 knots} = 12,000 \text{ pounds}